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Stochiometry Question

  • Thread starter SCGirl
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A 15-g sample of lithium is reacted with 15 g of fluorine to form lithium fluoride: 2Li + F2 --> 2LiF. After the reaction is complete, what will be present?
I think I start by dividing 15 g by the molar masses, but is the molar mass
2 x amu of Li and 2 x amu of F?
Thanks
 

Answers and Replies

help is hereeeee.....

i think you have to first find out what the limiting reactant is. and then use that amount to see how much lithium fluoride forms.
hope this helps :biggrin:
 
Gokul43201
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A 15-g sample of lithium is reacted with 15 g of fluorine to form lithium fluoride: 2Li + F2 --> 2LiF. After the reaction is complete, what will be present?
I think I start by dividing 15 g by the molar masses, but is the molar mass
2 x amu of Li and 2 x amu of F?
Thanks
Correct for fluorine, because it is made up of diatomic molecules (hence, F2), but not lithium, which is monoatomic.

PS: From the next time on, such questions should be posted under the Homework & Coursework forums found near the top of the main page.
 

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