- #1
nhrock3
- 415
- 0
[TEX]
_{c}\oint F*dr=_{\sigma}\iint(curlF)nds
[/TEX]
F(x,y,z)=(2z)i+(3x)j+(5y)k
[TEX]
_{\sigma}
[/TEX] is a part of a paraboloid [TEX]z=4-x^2-y^2[/TEX] where z>=0
on the x-y plane our paraboloid is 4=x^2+y^2
and the parametric view of it is:
x=2cost y=2sint z=0
so we get
[TEX]
_{c}\oint F*dr= (2z)dx+(3x)dy+(5y)dz
[/TEX]
i can't understand the next step[TEX]
_{c}\oint F*dr= (2z)dx+(3x)dy+(5y)dz=\intop_{0}^{2\pi}[0+(6cost)(2cost)+0]dt
[/TEX]
why??
_{c}\oint F*dr=_{\sigma}\iint(curlF)nds
[/TEX]
F(x,y,z)=(2z)i+(3x)j+(5y)k
[TEX]
_{\sigma}
[/TEX] is a part of a paraboloid [TEX]z=4-x^2-y^2[/TEX] where z>=0
on the x-y plane our paraboloid is 4=x^2+y^2
and the parametric view of it is:
x=2cost y=2sint z=0
so we get
[TEX]
_{c}\oint F*dr= (2z)dx+(3x)dy+(5y)dz
[/TEX]
i can't understand the next step[TEX]
_{c}\oint F*dr= (2z)dx+(3x)dy+(5y)dz=\intop_{0}^{2\pi}[0+(6cost)(2cost)+0]dt
[/TEX]
why??