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The equation is already balanced:

N2(g)+ 3H2(g) yields 2NH3 (g)

The questions asks for what is the chemical in excess? is it H2 or N2

I solved the problem but i want to make sure if it is right. this is what i did

6.0 moles of N2 (2 mol NH3 / 1 Mol of N2)= 12 mol of NH3

12.0 moles of H2 (2 mol NH3 / 3 mol H2)= 8 mol of NH3

I believe the answer is N2 because given amount is 12.0 moles and i got 8 mol of NH3 is it right or wrong please tell me.