Stoichiometry Help

1. Jul 12, 2006

Youngstarr1589

Aluminum oxide is formed from the reaction of metallic aluminum with oxygen gas. How many moles of Aluminum are needed to form 3.4 moles of Aluminum oxide?
Hint: This is a simple ratio problem. Just use the molar ratio from the balanced equation. This was covered in 5.09. Mass is not involved.

I need a lot of help with this problem... where do I start?

2. Jul 12, 2006

PPonte

First, it would help to write the chemical equation of the mentioned chemical reaction.

Second, balance the chemical equation.

Third, by the stoichiometric proportion, find the number of moles of alluminium that you would need to form 3.4 moles of aluminum oxide.

Hint: $$\frac{n_{Al}}{2} = \frac{n_{Al_2O_3}}{1}$$

:tongue:

3. Jul 16, 2006

Youngstarr1589

Ok this is what I have so far... I balanced the equation and got 4Al + O2
--> 2Al2O3 so then I did 3.4 molAl2O3 x 4mol Al = 6.8 mol Al ... is this right?

4. Jul 16, 2006

PPonte

Yes, you are correct.

:tongue:

5. Jul 31, 2006

Staff: Mentor

Funny, exactly this reaction forms basis of the stoichiometry calculations lecture.

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