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Stoichiometry help

  1. Nov 18, 2006 #1
    This is the question:
    How many phosphorus atoms are contained in 8.75 moles of H2P2O7? Put your answer in E-format with 1 number before and 2 numbers after the decimal place. e.g., 6.02 x 1023 would be input as 6.02E23.

    the answer is : 1.05E25 (1.05 × 1025)

    I really have no idea where to start. Please someone help me
  2. jcsd
  3. Nov 18, 2006 #2


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  4. Nov 19, 2006 #3
    You've been given 8.75 moles of H2P2O7, which contains 2x8.75 moles of H, 2x8.75 moles of P, and 7x8.75 moles of O. In one mole of anything (H2P2O7, P atoms, eggplants, etc), there are 6.02E23 particles.
  5. Nov 19, 2006 #4
    wow thank you so much. This explanation gave me the correct answer. I really appriciate your help a lot. This is part of our exam review. If I didn't know how to solve this problem I would miss it. I can't afford not knowing something b/c we only have 20 questions total. I need an A on tomorrow test to make an A average for the semester. You're the greatest :rofl: :rofl: :rofl: :rofl:
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