1. The problem statement, all variables and given/known data How many grams of potassium di chromate (K2Cr2O7) are present in 1 lit of its N/10 solution in acid medium? 2. Relevant equations gram eq = NV = g/E = xg/M 3. The attempt at a solution gram eq = NV = 0.1 * 1 = 0.1 g = gram eq * mol wt / valence factor (The valence factor I have taken as 14 because there are 7 oxygen atoms in potassium dichromate, which means in acidic solution there would be 14 H+ atoms) 0.1 * 294 / 14 = 2.1 How to proceed beyond this? The answer is one of the four:4.9, 49, 0.49, 3.9.