Stoichiometry problem

  • #1

Homework Statement


How many grams of potassium di chromate (K2Cr2O7) are present in 1 lit of its N/10 solution in acid medium?


Homework Equations



gram eq = NV = g/E = xg/M

The Attempt at a Solution



gram eq = NV = 0.1 * 1 = 0.1

g = gram eq * mol wt / valence factor (The valence factor I have taken as 14 because there are 7 oxygen atoms in potassium dichromate, which means in acidic solution there would be 14 H+ atoms)

0.1 * 294 / 14 = 2.1

How to proceed beyond this? The answer is one of the four:4.9, 49, 0.49, 3.9.
 

Answers and Replies

  • #2
OK, got it.

gram eq = no. of grams / Equ. wt

E = mol. wt/val factor = 294.2 / 6 = 49

g.e * E = 4.9.

Is this the answer?
 
  • #3
Borek
Mentor
28,778
3,252
Looks OK to me.
 

Related Threads on Stoichiometry problem

  • Last Post
Replies
2
Views
3K
  • Last Post
Replies
10
Views
2K
  • Last Post
Replies
1
Views
8K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
4
Views
3K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
1
Views
966
  • Last Post
Replies
24
Views
4K
  • Last Post
2
Replies
28
Views
2K
  • Last Post
Replies
1
Views
2K
Top