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Stoichiometry question

  1. Oct 14, 2012 #1
    1. Magnesium hydroxide, the active ingredient in milk of magnesia, neutralizes stomach acid, primarily HCl, according to the following reaction:

    Mg(OH)2(aq) + 2 HCl(aq) ---> 2 H2O(l) + MgCl2(aq)

    What mass of HCl, in grams, can be neutralized by a dose of milk of magnesia caontaining 3.26g Mg(OH)2?

    2. Mass A --> Amount A(in moles) --> Amount B(in moles) --> Mass B

    3. The attempt at a solution: 3.26g Mg(OH)2 X 1mol Mg(OH)2 /34.01g Mg(OH)2 X 2 mol HCl/ 1 mol Mg(OH)2 X 36.46g HCl/ 1 molg HCl = 6.99

    which is wrong, like I thought it would be. whats the right way to do this?
  2. jcsd
  3. Oct 14, 2012 #2
    This forum really is so unhelpful.
  4. Oct 14, 2012 #3


    User Avatar

    Staff: Mentor

    Nobody answered in 2 hours and you already know we are unhelpful?

    I have already answered your question elsewhere, is there a need to repeat it here? Check your molar masses.
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