1. The problem statement, all variables and given/known data Elemental (metallic) aluminum (Al) is reacted with HCl to yield aluminum chloride (AlCl3) and hydrogen gas (H2). How many grams of metallic aluminum would be required to produce 1 gram of pure hydrogen gas? 2. Relevant equations Al + HCl --> AlCl3 + H2 Balance Reaction: 2 Al + 6 HCl --> 2 AlCl3 + 3 H2 3. The attempt at a solution let Z = the amount of Al needed Z g Al * (1 mol Al / 26.98 g Al) * (3 mol H2/2 mol Al) * (2.02 g H2/1 mol H2) = 1 g H2 (6.04764 * Z) / 53.96 = 1 Z = 8.922 g Al I was hoping someone could look over this and see if did the correct process and came up with the right answer. Thanks!