JDGriffiths, 3rd ed, Prob. 1.33:(adsbygoogle = window.adsbygoogle || []).push({});

Givenv= xyx+ 2yzy+ 3xzz, check that Stoke's theorem is valid using the surface bounded by:

x = 0, 0 <= y <= 2, and 0 <= z = -y + 2. (See attached image.)

DJGriffiths Prob 1.33.bmp [Broken]

Area Integral Result:

[tex] \int \nabla \times \mathbf{v} \cdot d\mathbf{a} = \int (-2y) (\frac{1}{2} dy dz) = -4 [/tex]

Line Integral Result:

[tex] \int \mathbf{v} \cdot d\mathbf{l} } = \int (xy dx + 2yz dy + 3 xz dz) = \frac{8}{3} [/tex]

Stoke's theorem says they should be equal. What am I doing worng?

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# Homework Help: Stoke's Theorem check

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