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Stoke's Theorem formula

  1. Apr 1, 2015 #1
    1. The problem statement, all variables and given/known data
    Show that both sides of the Stoke's Theorem formula are valid for the function F= using the triangular surface on the y-z plane with corners at the origin, (0,2,0) and (0,0,2).

    2. Relevant equations
    Stokes Theorem equation( not sure how to write it out here)


    3. The attempt at a solution
    Took the curl of V, ended up with <-2y,-3z,-x> but when I go to integrate do I set x=0 and then dx=0 as well? So then, with y=2-z , bounds on the integrals are 0-2 and 0-(2-z) so (INT)(INT)(-3z)dydx with the bounds? But when I do this I end up with -4 ... Not sure where I am going wrong and I don't know how to prove the other side of the equation. Any help would be greatly appreciated.
     
  2. jcsd
  3. Apr 1, 2015 #2

    HallsofIvy

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    You left out the function so we can't answer your question!
     
  4. Apr 1, 2015 #3

    LCKurtz

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    Duplicate thread to https://www.physicsforums.com/threads/stokes-theorem.806286 [Broken]
     
    Last edited by a moderator: May 7, 2017
  5. Apr 2, 2015 #4

    micromass

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    The name is "Stokes", not "Stoke". So it should be "Stokes' theorem".
     
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