F = xi + x3y2j + zk; C the boundary of the semi-ellispoid z = (4 - 4x2 - y2)1/2 in the plane z = 0
(don't know how to write integrals on here, sorry)
double integral (curl F) . n ds
The Attempt at a Solution
curl F = 3y2x2k
n = k
curl F . n = 3y2x2
So I have a surface integral, which I think I can change to dA since the differential of the surface area is just 1dA...
Now this is where I'm stuck. How do i do the double integral with an ellipse? I tried it in rectangular coordinates but got some function I don't know how to integrate. Help!!