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**[SOLVED] Stokes' Theorem ( Surface Integral )**

## Homework Statement

Use stokes' theorem to find the value of the surface integral [tex]\int\int[/tex] (curl

**f**) dot

**n**) dS over the surface S:

Let S by the part of the plane z=y+1 above the disk x^2+y^2<=1, and let

**f**=(2z,-x,x).

## Homework Equations

http://img187.imageshack.us/img187/291/1fdf437d8e18a23191b63dfnj8.png

## The Attempt at a Solution

So, S has a minimum at (0,-1,0) and a maximum at (0,1,2). This gives me a right triangle, with one of its legs from (0,-1,0) to (0,1,0), and the other from (0,1,0) to (0,1,2). Its hypotenuse is 2sqrt(2) units long, meaning the slanted elliptical surface has a long axis length of 2sqrt(2) and a short axis length of 2 (from (-1,0,1) to (1,0,1)).

Now, should I somehow try to calculate the circulation around this region using stokes's theorem (maybe have a z component of the path being some sort of trigonometric function?), or is there a better way to do this (by still using Stokes' theorem, though)?

**EDIT: Nevermind. The best way is to just use x = cos(theta) , y = sin(theta), z = sin(theta)+1 after applying stoke's theorem.**

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