Projectile Motion: Calculating Distance and Velocity with Two Formulas

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In summary, a boy standing on the ground throws a stone with a velocity of 20 m/s at an angle of 30 degrees above the horizontal. The stone hits the wall of a nearby building at a position 3.0m above the level at which it was thrown. Two possible answers are: 1) the stone is still rising when it hits the wall, so the distance from the boy is 7.35m, and 2) the stone has reached its maximum height before hitting the wall, so the distance from the boy is 14.7m. The formula used to calculate these distances is Range=(Vo^2*sin2theta)/(|g|) and V^2x = V^2ox
  • #1
jason.frost
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1. A boy standing on the ground throws a stone with velocity 20 m/s at an angle of 30 degrees above the horizontal. It hits the wall of a nearby building at a position 3.0m above the level at which it was thrown. How far is the from the boy? (Two answers are possible. Give both. One represents the stone on its way up, the other on the way down.)



2. I guess I mainly need some help with which formula to use.



3. I am thinking that you will use Range=(Vo^2*sin2theta)/(|g|) and V^2x = V^2ox + 2axX. Sorry if those look bad. Is there any sub or sup script formatting? Am I thinking right with the formulas? I really don't even know what the second one finds for you.
 
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  • #2
You would use

[tex]y(t) = y_o + v_{yo} t - \frac {1}{2} g t^2[/tex]

for vertical motion and

[tex]x(t) = x_0 + v_{xo} t[/tex]
for horizontal motion. (Btw, see this thread for LaTex formatting.)
 
  • #3
Thanks.

What does the question mean by one answer is for "the way up and the other for the way down"?
 
  • #4
The stone could still be rising when it hits the wall ("on the way up") or it might have reached its maximum height prior to hitting the wall ("on the way down"). The two scenarios yield two different answers.
 

1. What is the Stone Throw Motion question?

The Stone Throw Motion question is a physics problem that involves determining the trajectory of a stone thrown through the air, taking into account factors such as initial velocity, angle of projection, and gravitational acceleration.

2. How is the Stone Throw Motion question solved?

The Stone Throw Motion question is typically solved using mathematical equations and principles from projectile motion, such as the equations of motion, trigonometry, and calculus. These calculations can be done by hand or with the help of a computer program.

3. What are the key variables in the Stone Throw Motion question?

The key variables in the Stone Throw Motion question include the initial velocity of the stone, the angle of projection, the height of the launch point, the gravitational acceleration, and the horizontal and vertical components of the stone's motion.

4. How does air resistance affect the Stone Throw Motion question?

Air resistance can have a significant impact on the trajectory of a thrown stone. As the stone moves through the air, it experiences a force in the opposite direction of its motion, which can cause it to slow down and deviate from its expected path. Calculating and accounting for air resistance can make the solution to the Stone Throw Motion question more accurate.

5. What real-life applications does the Stone Throw Motion question have?

The Stone Throw Motion question has various real-life applications, such as predicting the trajectory of objects thrown in sports like baseball or javelin throwing. It is also used in engineering and construction to determine the trajectory of projectiles, such as bullets or rockets, and to design structures that can withstand the forces of objects in motion.

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