A car is moving along a flat road at a constant 18ms^-1 it then applies the breaks with a force of 3600N
If this car is then moving down a hill at 18ms^-1 the same breaking force is applied is the cars stopping distance larger or smaller or the same?
Eκ = 1/2 M V^2
The Attempt at a Solution
I said the same as the stopping distance is proportional to the Kinetic energy of the car is the thinking distance is not relevant so as the KE of the car is the same I assumed the stopping distance would be the same.
I then asked by brother who is rather good at maths but did not take physics and he was a bit indecisive and said it depends on how it was being marked. Can you guys shed any light on this?