1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Stopping Distance

  1. Oct 7, 2006 #1
    Three cars (cars F, G, and H) are moving with the same velocity, and slam on the brakes. The most massive car is F, and the least massive is H. Assuming all 3 cars have identical tires, which car travels the longest distance to skid to a stop?

    Will they all travel the same distance in stopping?
    If mgh = mv^2/2 for each car:

    F – (3mv^2)/2 = 3*mgh h = v^2/2g
    G – (2mv^2)/2 = 2mgh h = v^2/2g
    H – mv^2 = mgh h = v^2/2g

  2. jcsd
  3. Oct 7, 2006 #2


    User Avatar
    Staff Emeritus
    Science Advisor

    The same tires implies the same coefficient of friction, u or [itex]\mu[/itex].

    The force of friction applies, Ffriction = [itex]\mu[/itex]mg, and the energy dissipated is Efriction = Ffriction*d, where d is the distance traveled.

    Find dF = dG = dH.
  4. Oct 7, 2006 #3
    How do I find the energy of friction to find each car's d?

    To find d, it would be E/F?

    Thanks again.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Stopping Distance
  1. Stopping Distance (Replies: 9)

  2. Stopping Distance (Replies: 5)

  3. Stopping distance (Replies: 9)

  4. Stopping distance (Replies: 8)