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Strain on Brain

  1. Jan 25, 2004 #1
    Ram has a rectangular piece of card board out of which he clipped away the largest possible square and was left with a piece similar in shape to the original piece. The area of the piece remaining with Ram forms approx what percent of the original piece
  2. jcsd
  3. Jan 25, 2004 #2


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    This is a "golden rectangle" problem isn't it?

    Let the original rectangle have length l and width w. We an assume that w< l. The largest square that can be cut from that is "w by w" leaving a rectangle of sides w and l-w.

    Now which is larger, w or l-w? If we started with a skinny rectangle, in which l was not only larger than w but larger than 2w, l-w is still larger than w and saying that this new rectangle is similar to the orginal says that l/w= (l-w)/w (writing longer side over shorter for both rectangles). But that's the same as l= l-w which is impossible.

    Thus, in the new rectangle, the longer side (corresponding to l in the original rectangle) has length w and the shorter l-w. Since the new rectangle is similar to the original, we have w/(l-w)= l/w or
    w2= l2- lw. Dividing both sides by l2, (w/l)2= 1- w/l. We can think of this a quadratic equation and solve for w/l.

    The area of the new rectangle is w(l-w)= lw- w2. The area of the original rectangle was lw. The new rectangle has area
    (lw- w2)/lw= 1- (w/l).
  4. Jan 26, 2004 #3
    Thanks Halls I knew i have to apply the prop u quoted but never applied it was just an odd time
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