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## Homework Statement

An astronaut runs out of fuel in his power pack while drifting at 1.0 m/s away from the Space Shuttle. The astronaut removes his 25.0 kg power pack and throws it away at 2.9 m/s relative to the shuttle and in the direction away from the shuttle. The mass of the astronaut plus the space suit, minus the power pack is 103.0 kg. Calculate the new relative speed of the astronaut towards the shuttle. Take the velocity away from the shuttle to be minus

## Homework Equations

m1*v1(final) + m2*v2(final) = 0

## The Attempt at a Solution

m1 = 103.0kg (astronaut)

m2 = 25.0kg (power pack)

v1(final) = ? (astronaut)

v1(initial) = -1.0 m/s (astronaut)

v2(final) = -2.9 m/s (power pack)

So I am solving for v1(final):

v1(final) = (-m2*v2)/m1

= (-25.0kg*-2.9m/s)/103.0 kg

= .703 m/s

So I thought this would be the astronauts new velocity but it is not. I'm really not sure how to tie in the astronauts initial velocity of -1.0 m/s into the momentum equation.