- #1

- 2,259

- 1

But take the same equation convert it to n/(n+1)/(n+2) as n-> infinity results in the limit 1.

What is going on? The expression is the same yet you get two different limits. Something is wrong.

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter pivoxa15
- Start date

- #1

- 2,259

- 1

But take the same equation convert it to n/(n+1)/(n+2) as n-> infinity results in the limit 1.

What is going on? The expression is the same yet you get two different limits. Something is wrong.

- #2

Curious3141

Homework Helper

- 2,850

- 87

Take n/(n+1)-n/(n+2) as n->infinity results in the limit 0

Correct.

But take the same equation convert it to n/(n+1)/(n+2) as n-> infinity results in the limit 1.

How? The expression is [n/(n+1)]/(n+2). Working from left to right, the limit reduces to (n/n)/(n+2) = 1/(n+2) = 0. (Very sloppy, but I can't do the tex now).

- #3

- 2,259

- 1

I see. I made a mistake in my OP.

- #4

HallsofIvy

Science Advisor

Homework Helper

- 41,847

- 965

?? And if you were to "convert" it into something

But take the same equation convert it to n/(n+1)/(n+2) as n-> infinity results in the limit 1.

What is going on? The expression is the same yet you get two different limits. Something is wrong.

- #5

Curious3141

Homework Helper

- 2,850

- 87

?? And if you were to "convert" it into somethingelseit isnot equal toyou would get yet a different answer! Garbage in, garbage out.

The expressions are identically equal.

Share: