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- Thread starter Calpalned
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- #2

jedishrfu

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How are you computing the tangents?

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- #4

Mark44

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Just show us your work, not an image of it, especially one that doesn't render.

- #5

Mark44

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When t = 2, x = 2 and y = -4, just as you say. And dy/dx = 0 when t = 2, so the tangent is horizontal at (2, -4). Why do you think that the tangent is vertical when t = 2?

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- #7

Mark44

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Right, but they occur for two different values of t.

When t = -1, (x, y) = (2, -4) and the tangent is vertical.

When t = 2 you get (2, -4) again, but this time with a horizontal tangent.

To find the values of t, I solved the equation t

- #8

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Thank you so much, I understand now

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