- #1

Dell

- 590

- 0

all that i can see here is the obvious,

since it is a thin walled tube i can use the following

[tex]\tau[/tex]

_{max}=T*r

_{avg}/J

J=2pi*r

_{avg}

^{3}*t

dP/dt=T/(GJ)

now i know that r

_{avg}=c+t/2

what i also think is that at point 2, (P2,S2) i am at the critical point of the joint where it reaches its maximum so S2=[tex]\tau[/tex]

_{max}

but that's all i manage to get and nowehre near any kind of ratio c/t