1. The problem statement, all variables and given/known data Two wires are made of the same metal but have different dimensions. Wire 1 is 4 times longer and twice the diameter of wire 2. If they are both under the same load, compare (a) the stresses in the two wires and (b) the elongations of the two wires. 2. Relevant equations stress = F/A elongation = ΔL/L 3. The attempt at a solution For the first part I did F/A F/((x/2)^2*3.14) 2F/3.14x^2 F/A F/((x/4)^2*3.14) 16F/3.14x^2 So it should be that the thinner wire experiences 8 times as much stress as the thicker wire. However the correct answer is that the thinner wire experiences 4 times as much stress.