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bored axially to produce a cylinder of uniform thickness. If this cylinder is then subjected

to an axial tensile load of 75kN, what is the maximum diameter of the bore possible if the

stress in the cylinder is not to exceed an allowable stress based on a factor of safety of

1.33 of the yield stress

Yield Stress: 320MPa

E: 205GPa

B = bore radius

Calculated allowed stress σ/1.33 = 241MPA

I use σ = F/A

A=F/σ

∏*( r - B)

^{2}= 75000/241MPa

∏*( 0.0125 - B)

^{2}= 75000/241MPa

Is this the right up to now? i have continued to work this out and dont get the correct answer of 5.59 x 10

^{-6}