1. The problem statement, all variables and given/known data The stress distribution along the section of a bar is shown below. From this distribution, find the approximate axial force P in kip. 2. Relevant equations δavg=P/A A= (.6+.6)(.5) δavg=30ksi 3. The attempt at a solution P=(30ksi)(.6in2)=18kip It says this answer is wrong but i don't see where i am going wrong here? .8in is the diameter of the whole so it is not considered when finding the area.