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Stress in steel and concrete

  1. Oct 8, 2016 #1
    1. The problem statement, all variables and given/known data
    here's the question , Part of solution was given , but not the final ans . I have tried to do , but i need someone to verify my ans .

    2. Relevant equations

    3. The attempt at a solution
    Since , stress of steel is 12.5 times of stress of concrete . The max allowable stress in steel is 175MPa , while for the concrete is 20MPa . The author choose stress of steel = 175MPa , because by doing so , the stress in concrete is 14MPa(<20MPa) ,
    But if the author choose stress of concrete = 14MPA , then the stress of steel would be = 12.5(14) = 250MPa , which is (>175MPa)

    So , in 2nd part , my working = (17.5x10^6)(Area of steel) + (14x10^6)(10 Area of steel ) = 1000x10^3

    so , Area of steel = 0.52(mm^2) , is my ans and concept correct ?

    Attached Files:

  2. jcsd
  3. Oct 9, 2016 #2
    or there's something wrong with my calculation ?
  4. Oct 9, 2016 #3
    Anyone can response?
  5. Oct 10, 2016 #4
    anyone ?
  6. Oct 10, 2016 #5
    Or each of the steel and concrete received forces of 1000kN ?
  7. Oct 11, 2016 #6


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    The second part doesn't look right.

    Note the area of the concrete, a2, is 10 times the area of the steel. What is the area of the steel?

    What does one assume about load P on the combined area?
  8. Oct 13, 2016 #7
    Your answer of 0.52 mm2 seems improbable, if not impractical, and so, without looking at your working, I am inclined to try a different approach. The usual problem here is often the units; so stick to, say N and mm. Try a concrete area of say 50 mm x 50 mm. At 14 MPa (ie N/mm2) , its resistance is? The steel would have a thickness of 250/200 = 1.25 mm and this does seem practical. So what is the steel's resistance? When you add these two resistances together, how does this compare with the applied load? So how far are you from the problem now you have a better feel for the quantities involved? - perhaps this is not the help you were expecting, but worth trying?
  9. Oct 16, 2016 #8
    sorry , i made a typo , it should be (175x10^6)(Area of steel) + (14x10^6)(10 Area of steel ) = 1000x10^3
    Area of steel = 3.174(mm^2) , is it correct now ?
  10. Oct 16, 2016 #9
    total force = pressure act on steel (area of steel) + pressure on concrete (area of concrete)
    = pressure act on steel (area of steel) + pressure on concrete (10 area of steel)
  11. Oct 16, 2016 #10
    Still looks funny. I am struggling to visualise 3.174 mm2. You haven't declared your units. Can you explain the 10^6 and the 10^3 in your corrected equation?
  12. Oct 16, 2016 #11
    10^6 = MPa , 10^3 = kN , are they wrong ?
  13. Oct 17, 2016 #12
    are they wrong ?
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