# Strings and Spring (1 Viewer)

### Users Who Are Viewing This Thread (Users: 0, Guests: 1)

I

#### izmeh

##### Guest
I have the following problem

Pulling up on a rope, you lift a 4.25-kg bucket of water from a well with an acceleration of 1.80 m/s². What is the tension in the rope?

What part exactly does the acceleration play in this scenario?

#### Doc Al

Mentor
Originally posted by izmeh
What part exactly does the acceleration play in this scenario?
The net force on an object determines its acceleration. Given the acceleration, you can find the net force. Tell us what you know about Newton's second law.

I

net force = ma
a = f/m
1.80 = f/4.25
f = 7.65

#### Doc Al

Mentor
First step: Describe all the forces acting on that bucket! Then add them up to find the net force.

Draw yourself a diagram.

I

#### izmeh

##### Guest
there is the force of me pull it up @ 1.80m/s²
the mass 4.25 pulling down...

#### Doc Al

Mentor
Originally posted by izmeh
there is the force of me pull it up @ 1.80m/s²
the mass 4.25 pulling down...
There is a force pulling up, that's the tension (T) in the rope. There's also a force pulling down, the weight (not mass!) of the bucket&water. (Note: gravity pulls on the mass, that pull is the weight. You can calculate the weight by multiplying the mass by g, the acceleration due to gravity. g = 9.8 [m/s2])

The net force is (choosing up as positive):

Fnet = T - mg

From Newton's second law:

Fnet = ma

Now it's your turn. You know a (it's 1.8 m/s2 upwards) and you know m . Find T. Give it a try.

### The Physics Forums Way

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving