- #1

captainjack2000

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## Homework Statement

I have the ionic compound cesium chloride and have been asked to use the equation

p(k) = (sum over j) exp(-iK.r)f(k)

to find the structure factor for x-ray diffraction from cesium and explain why it can take two values. It also asks how you would expect the intensities of the bragg reflections in the x-ray patterns of cesium, cesium chloride and cesium iodid to compare.

## The Attempt at a Solution

I know that cesium chloride has a simple cubic structure with Cs at 0,0,0 and Cl at 1/2 , 1/2, 1,2

So I found the recipricol lattice vectors to be a*=(2*Pi/L)x b*=(2*Pi/L)y and c*=(2*Pi/L)z

The recipricol lattice vector is K=ha*+kb*+lc*

so

p(k) = f(Cs)exp(0) + f(Cl)exp(-iK.(L/2,L/2,L/2))

=f(Cs) + f(Cl)exp(-i*pi*(h+k+l))

which is =f(Cs) + f(Cl) if h+k+l is even or =f(Cs)-f(Cl) if h+k+l is odd.

I'm not sure where the -i*pi*(h+k+l) part came from? are h,k,l just 2,2,2??

for the second bit I know that the intensity is proportional to the structure factor squared...

not sure where to go from here.