Is 2,4-Pentanedione a ring structure or just a hydrocarbon chain with double-bonded O's on C 2 and 4? When showing the reaction with the Iodoform test what would the chemical equation be? I know it is 2,4-Pentanedione NaOH --> I know how this would work with a single double-bonded O but how I2 would it work with two? Would the result be... CH3CIONaCIOCH3 with 2 CHI3 (iodoform) derivatives in the solution? Please help. Thanks.