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Struggling with a chain rule problem

  1. Mar 21, 2013 #1
    1. The problem statement, all variables and given/known data

    Let [itex](u,v)=\mathbf{f}(x,y,x)=(2x+y^3,xe^{5y-7z})[/itex]

    Compute [itex]D\mathbf{f}(x,y,z),\;\partial (u,v)/\partial(x,y),\;\partial (u,v)/\partial(y,z)\text{ and }\partial (u,v)/\partial(x,z)[/itex]

    2. Relevant equations

    -chain rule

    3. The attempt at a solution

    well I can get [tex]D\mathbf{f}(x,y,z)=\left[\begin{matrix} \partial u / \partial x & \partial u / \partial y & \partial u / \partial z \\ \partial v / \partial x & \partial v / \partial y & \partial v/ \partial z \end{matrix}\right]=\left[\begin{matrix} 2 & 3y^2 & 0 \\ e^{5y-7z} & 5xe^{5y-7z} & -7xe^{5y-7z}\end{matrix}\right][/tex]and I can see that if I ignore the variable that is not in the partial, and take the determinant of that 2x2 matrix, then I get the partial derivative I want. My questions is what am I doing? what happens if it is a 3x2 matrix instead of a 2x3? does this "method" still work?
     
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  3. Mar 21, 2013 #2

    Fredrik

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    I don't understand the question. You seemed to have solved the problem. (The solution looks good to me). What determinant are you talking about?
     
  4. Mar 21, 2013 #3
    I do not understand what you mean.
     
  5. Mar 21, 2013 #4
    well I have the matrix derivative, but I still need to get those three partial derivatives. For example I can see that [tex]\frac{\partial (u,v)}{\partial (x,y)}=\left|\begin{matrix} 2 & 3y^2 \\ e^{5y-7z} & 5xe^{5y-7z} \end{matrix}\right|=(10x-3y^2)e^{5y-7z}[/tex]so I am taking the components of my matrix derivative that are in question and taking the determinant of the 2x2 matrix. I just don't get why I am doing this. I don't understand what i'm doing, only how to do it.
     
  6. Mar 21, 2013 #5

    Fredrik

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    I'm not familiar with the notation ##\partial (u,v)/\partial(x,z)##. How is it defined? I can see how you're computing it, but is it defined as that determinant?
     
  7. Mar 21, 2013 #6

    Zondrina

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    ##\frac{∂(x_1,...,x_n)}{∂(v_1,...,v_n)} =

    \left| \begin{array}{ccc}
    ({x_{1}})_{v_1} & ... & ({x_{1}})_{v_n} \\
    ... & ... & ... \\
    ({x_{n}})_{v_1} & ... & ({x_{n}})_{v_n} \end{array} \right|##

    It's the Jacobian.
     
  8. Mar 21, 2013 #7
    If you are supposed to find Df, which is a matrix of the partial derivatives of all the components against all the variables, which happens to be 2x3 in this case, then why do you care about a 2x2 matrix (and its determinant) of some partial derivatives? And the answer is, you should not. Just compute all the partials, as requested, and be done with that.
     
  9. Mar 21, 2013 #8

    Fredrik

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    Is it really? The u and v that are given in the problem are functions of three variables, but only two of them appear in these "Jacobians".
     
    Last edited: Mar 21, 2013
  10. Mar 21, 2013 #9

    Fredrik

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    Apparently he's not just supposed to find Df(x,y,z). The problem is asking specifically for those determinants.
     
  11. Mar 21, 2013 #10
    but that's the thing. I'm getting the 3 requested partials by taking the determinant of those 2x2 matrices. I computed the matrix derivative as requested, but I am not sure what I am actually "doing" when I am asked to find those partial derivatives. I'm not even sure what the thing I am finding represents. All I know how to do is compute it for the test!

    my textbook is "Folland, Advanced Calculus" and this is chapter 2.10, i case anyone has that book
     
  12. Mar 21, 2013 #11

    Fredrik

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    But the requested things aren't partial derivatives, are they? Can you post the definitions and theorems that make you think that you should compute those determinants. (I'm not saying that you're wrong, only that I need to see some definitions).

    There's no preview at google books, and I was unable to find a pdf online.
     
  13. Mar 21, 2013 #12
    hmm ok well I think I will have to put this one on hold until the weekend. afterall I can get the marks on the test and that's what school all about right! haha.
     
  14. Mar 21, 2013 #13
    It seems to me that you know how to get the result, but you don't really understand the significance of the result. Is that correct? I am not familiar with that textbook, and the comments on Amazon are not very encouraging, but perhaps you should try re-reading the relevant part on theory.
     
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