Struggling with AP Multiple Choice: ky Differential Equation

tandoorichicken
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Heres an AP multiple choice problem that's giving me some trouble:

If [tex]\frac{\,dy}{\,dt} = ky[/tex] and k is a nonzero constant, then y could be

a) [itex]2e^{kty}[/itex]
b) [itex]2e^{kt}[/itex]
c) [itex]e^{kt} +3[/itex]
d) [itex]kty + 5[/itex]
e) [itex]\frac{1}{2}ky^2 + \frac{1}{2}[/itex]

Dont quite know where to begin?
 
You have two choices.

#1 (probably the hardest way, but useful if you forgot how to solve it): Take all of the answers and plug them in. See which one works.

#2: Separate the variables and integrate.

dy/y = k*dt
ln(y) = kt + C
y = e^(kt + c) = Ae^(kt)

cookiemonster
 
Actually, for this problem, I suspect that most people would just differentiate each of the answers.
 

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