The problem is:(adsbygoogle = window.adsbygoogle || []).push({});

Find the area of the surface of revolution generated by revolving the curve

e^(8θ), 0≤θ≥½π around the y-axis.

θ= Theta

½π= 1/2*pi

sqrt= sqare root

² = squared

Here's my work:

ds = sqrt( (e^(8θ))² + (e^(8θ))² )dθ

dθ = (e^(8θ)sqrt(2)

x = rcos(θ)= e^(8θ)cos(θ)

A = 2*½π*sqrt(2)*integral of (e^(16θ)cos(θ)) between 0 and ½π

I solved the integral and I got

2*½π*(2)/257*(e^(8θ)-16))

When I plugged the answer online, I got it wrong. Can someone please figure out what's wrong?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Stuck on a problem!

Can you offer guidance or do you also need help?

Draft saved
Draft deleted

Loading...

Similar Threads for Stuck problem |
---|

A Maximization problem using Euler Lagrange |

A Maximization Problem |

I A question about Vector Analysis problems |

B Square root differential problem |

B Integrating Problem |

**Physics Forums | Science Articles, Homework Help, Discussion**