Stuck on a Related Rates Triangle Problem

  • #1
361
1
Hi Again,

I am doing a question on related rates that I have become stuck on.

The height (h) of an equilateral triangle is increasing at a rate of 3cm/min. How fast is the area changing when h is 5cm?

I know that the area of a triangle is bh/2, but after that I am stuck :redface: I tried deriving it using the chain rule so that I could substitute h and the rate of h, but I don't think that i was doing it the right way. If anyone could direct me here I would really appreciate the help.
 

Answers and Replies

  • #2
Here are some things to consider, the height "h" of an equilateral triangle is

[tex]\frac{1}{2}\sqrt{3}s[/tex]

where "s" is the length of one side.

The area of this triangle is equal to

[tex]\frac{1}{2}sh[/tex]

See any substitutions?
 
  • #3
[tex]
\frac{dA}{dt} = \frac{dh}{dt} * \frac{dA}{dh}
[/tex]
 

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