- #1
Mishi
- 7
- 0
Homework Statement
Show that the exact value of tan°43' is [itex]\frac{\sqrt{5}-1}{2}[/itex]
Homework Equations
The Attempt at a Solution
[itex]tan2x = \frac{2tanx}{1-tan^{2}x}[/itex]
[itex]\frac{2tan31° 43}{1-tan^{2}31° 43'}[/itex]
From here, i got stuck or I'm doing it wrongly, i forgot how to do it.
Btw, I'm new here, please tell me if i posted it in the wrong place xD