- #1
Flucky
- 95
- 1
Hi all sorry the title couldn't be more descriptive.
I'm having a bit of a brain block with this equation (it's the very end of a problem).
N([itex]\frac{5}{6}[/itex])[itex]^{N-1}[/itex] > [itex]\frac{27}{5}[/itex]
My line of thought was to get the first N in terms of the power N-1..
How do I find N?
I'm having a bit of a brain block with this equation (it's the very end of a problem).
N([itex]\frac{5}{6}[/itex])[itex]^{N-1}[/itex] > [itex]\frac{27}{5}[/itex]
My line of thought was to get the first N in terms of the power N-1..
How do I find N?