Stuck on an integration problem.

  • Thread starter Sir.Aaron
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  • #1
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This is a problem I tried a couple days ago and I got stuck on some parts.Here is the problem

[tex]/int sin^2 3xcos^5 3x dx[/tex]



Can anyone help me out?
 
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Answers and Replies

  • #2
mathwonk
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ignore the threes.


an odd number of cosines or sines is equivalent to one of them and an even number of the other, so this is basically sin^6cos, set u = sin(x), and du = cos(x)dx
 
  • #3
mathwonk
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this is basic by the way. are you studying on your own? are you reading the book? do you have a teacher? this is really a simple one. so somehting is amiss here.
 
  • #4
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Yes I am teaching my self. Im still in 10th grade.Thank you for the help
 
  • #5
VietDao29
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Sir.Aaron said:
Yes I am teaching my self. Im still in 10th grade.Thank you for the help
Oh, I started self-studying calculus when I was in grade 10th, too. :approve:
Good luck, man. :smile:
 
  • #6
mathwonk
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forgive my rudeness, you are way ahead of me at your age.

please take my criticism in the vein of the doctors comment that my wife was in "reasonably good condition for a woman in her early 20's" when she was actually 35!.
 
  • #7
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Maybe you could ask your teacher if he/she could refer you to a college or something so you could study there (just being there on their courses).
I started Calc. at 8th grade and was tutored along with college students at a nearby college (or university, as it is called in Sweden where I live)
 
  • #8
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myspip said:
Maybe you could ask your teacher if he/she could refer you to a college or something so you could study there (just being there on their courses).
I started Calc. at 8th grade and was tutored along with college students at a nearby college (or university, as it is called in Sweden where I live)
Thats what I want to do but my problem is I dont know Geometry. I dont understand why I cant understand it. This summer I learned Trig(I bought trig for dummies,awsome book) and started on Calculus. I am currently on integration by parts. I also love physics.
 
  • #9
mathwonk
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the best book i know of on geometry is Geometry, by harold jacobs. i highly recommend it and learning geometry before going to college (or pursuing calculus much further).

hows your algebra? thts the main stumbling block for college calculus.

but in my opinion, a very harmful trend these days is teaching kids calculus befiore they learn algebra and geometry.
 
  • #10
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mathwonk said:
the best book i know of on geometry is Geometry, by harold jacobs. i highly recommend it and learning geometry before going to college (or pursuing calculus much further).

hows your algebra? thts the main stumbling block for college calculus.

but in my opinion, a very harmful trend these days is teaching kids calculus befiore they learn algebra and geometry.
Ya thats what I did I made the mistake of learning trig and calculus. Im supposed to be taking a test tomarrow, if I pass this test and another one I get moved into the 12th grade math class. Thanks for the Book recomendation but its $67.00, and for a out of work 10th grader thats a bit steep,lol. My fear is there will be a lot geometry on the tests and that going to make me fail the tests.
 
  • #11
mathwonk
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Geometry (ISBN: 0716704560)
Harold R. Jacobs
Bookseller: Great Buy Books
(Lakewood, WA, U.S.A.) Price: US$ 13.23
[Convert Currency] Shipping within U.S.A.:
US$ 3.75
[Rates & Speeds]
Book Description: W.H. Freeman & Company, 1974. Hardcover. Book Condition: GOOD. Dust Jacket Condition: ACCEPTABLE. USED Ships Within 24 Hours - Satisfaction Guaranteed!. Bookseller Inventory # 2762629
 
  • #12
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hehe lol. only 3,75 dollars?
My books cost up to 100 dollars each (college math books, last for 2 month).
Well, sometimes you have to invest money on your education (not saying that you should put all your money on it, but a bit maybe). Also, try asking some college students if you can buy their books (second-hand that is)
 
  • #13
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Sorry to bring this old topic back, but I cant seem so figure this problem out. Its cause of the trig in the problem. So can someone do the whole problem so I can see how to do it?
 
  • #14
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Following mathwonk, we note that cos^2(x) = 1 - sin^2(x), so that cos^4(x) = (1 - sin^2(x))^2. Hence

sin^2(x)cos^5(x) =
sin^2(x)(1 - sin^2(x))^2 * cos(x)

Now make the substitution u = sin(x).
 

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