- #1

- 265

- 2

## Homework Statement

The question asks to calculate the jerk of an object (both its direction and magnitude) in uniform circular motion.

## Homework Equations

j=d(a)/dt

## The Attempt at a Solution

I know that the direction is opposite the velocity vector (I did this by drawing a circle and taking a limit of average acceleration as t approaches 0). I also know that the parallel component of jerk is 0 because the parallel component of acceleration in UCM is 0. I am stuck on the magnitude of the perpendicular component. I know that

[tex] \vec{a}_{\perp} = \frac{v^2}{2}(-r) [/tex] (the r is a unit vector)... can I just take the derivative of this? wouldn't that be 0? because v^2/r is a constant and there is no t. i am suck.

Last edited: