- #1

SheldonG

- 50

- 0

I am really stuck on this one. I write the force equation as

mg sin 20 - u mg cos 20 = 0

And it seems to me that the additional frictional force that must be supplied by moving the load would then be given by sin 25 - sin 20. But I have no idea how to turn this value into a distance. I have tried using torques around the center, like this:

mgd/4 = (sin 25 - sin 20)mg

But this is so small it can't be right. Any suggestions that would help shake me loose would be appreciated.