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Stuck on this AC Circuit Problem

  1. Jan 24, 2014 #1
    1. The problem statement, all variables and given/known data

    Series_RC_Circuit.jpg

    For the circuit in question1above: R=(3.74x10^2) (Ω), C=(3.8700x10^-7) (F), f=(4.610x10^3) (Hz) and the peak amplitude of the voltage of the source (ES)=(6.185x10^1) (V). Calculate the instantaneous value of the voltage across the capacitor at t=(4.110x10^-5) (s) after the positive zero crossing of the current waveform.


    2. Relevant equations

    v=Vmsin(2*pi*f *t + θ)
    Xc = 1/(2*pi*f*C)
    θ = tan^-1(Xc/R)

    3. The attempt at a solution

    The part that's confusing me is where it says "after the positive zero crossing of the current waveform". I've tried using the phase shift angle and subtracting 90 degrees to put into equation:
    v=Vmsin(2*pi*t + θ). I've also tried using just the phase shift angle, using only 90 degrees, and using 90 degrees + phase shift angle, and none have gotten me an answer any where near what it's supposed to be.

    What I've done so far is calculated Xc = 89.2 ohms
    then calculated phase shift = 13.41 degrees
    then tried a number of different combinations of angles using the formula v=Vmsin(2*pi*t + θ)

    Could anyone tell me where I'm going wrong? This question is driving me nuts :(

    after looking at the question some more, perhaps this is what I am supposed to do?

    vr = vmsin(2*pi*f*t - 13.41 degrees (0.216368996rad) = 51.16253852 V
    vs = vmsin(2*pi*f*t) = 57.43068007 V

    vc = vs - vr = 57.43068007 V - 51.16253852 V = 6.268 V
     
    Last edited: Jan 24, 2014
  2. jcsd
  3. Jan 24, 2014 #2

    Simon Bridge

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    You have the voltage waveform - what is the corresponding current waveform?
    (i.e. what is the relationship between voltage and current?)
     
  4. Jan 28, 2014 #3
    Isn't the capacitor voltage lagging the current by 90 deg? I'm not sure how to incorporate the phase shift though, and I've tried this question a few more times and still end up with an answer that's way off.
     
  5. Jan 29, 2014 #4

    Simon Bridge

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    The phase shift comes out automatically if you use complex impedances ... if you are just using reactances, you should use a phasor diagram: the loop law voltages add head-to-tail.
     
  6. Jan 30, 2014 #5
    Ah thanks! With the same problem with different numbers I had R = 350, C = 380nF, f = 3.91kHz, (Es)m = 29.86v

    Got an answer of -3.12v which was correct.

    It became much simpler now that I know the phase shift isn't used... just used formula (Vc)msin(2*pi*f*t-(pi/2)) after calculating the other stuff and it gave me the right answer

    Thanks for the help!
     
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