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Stuck on this function

  1. Sep 27, 2005 #1
    I'm going through the review section of the Stewart Calculus text and I'm stuck on this problem.

    f_0(x) = x^2
    f_0(f_n(x)) = f_{n+1}(x) , n = 0,1,2...
    how do you solve for
    Last edited: Sep 27, 2005
  2. jcsd
  3. Sep 27, 2005 #2
    The only place I can think to start is making [itex] (f_n(x))^2 = f_{n+1}(x) [/itex], but that's as far as I got
  4. Sep 27, 2005 #3


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    Now, f1(x) = f0(f0(x)) = f0(x2) = x4
    f2(x) = f0(f1(x)) = f0(x4) = x8
    f3(x) = f0(f2(x)) = ...
    f4(x) = f0(f3(x)) = ...
    So what's fn(x)?
    Can you go from here?
    Viet Dao,
  5. Sep 27, 2005 #4
    From that I get [itex] f_n(x) = x^{2^{n+1}} [/itex] but that doesn't work for [itex] f_0(x) = x^2 [/itex]. That's the same answer the book has, so maybe I wrote the requirements down wrong. I'll have to check when I get home if this had to work for 0.
  6. Sep 27, 2005 #5
    Yes it does. Never mind.

    Thanks Viet Dao!
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