ok heres the problem i haven't taken trig for like 2 years and suddenly i have been thrown back in to it...(adsbygoogle = window.adsbygoogle || []).push({});

problem: 2 cos 2x - 4 cos x + 3 = 0 0 < x < 2 pi

my work (used cos 2 x = 2 cos^2 x - 1)

4 cos^2 x - 2 - 4 cos x + 3 = 0

4 cos^2 x - 4 cos x + 1 = 0

ok now here is my problem if i try and factor it out i ll be left with the a really ugly 1/ ( 4 cos x)

is there another equation i could use... is my logic flawed... is there an easier way... do i just have to do it the ugly way... ???

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# Homework Help: Stuck on this hard trig problem

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