# STUDYING FOR TEST, need a tutortial

1. Nov 17, 2004

### ElectricMile

ok..haveing trouble understanding some examples in the book....

1) 1000kg rocket is fired striat up, need rocket to escape and never return. what speen does rocket need to escape from grav pull to never come back?(non rotating earth)

i know rocket cant stop so or it will be drawn back into earth. so...
K2+U2=K1+U1 is:
0+0=(1/2)m*v^2 - (GMm)/R)

whats with the 0+0?

then it goes to:
Vescape= v1 = SQRT(2GM/R)

howd they get to that equation??
i know the answers and stuff its in the book, i just dont know how they got to those equations

2. Nov 17, 2004

### thecolor11

For escape velocity, you only need enough speed so that you escape the gravitational potential of the object. Therefore, any kinetic energy at infinity would be wasteful. So K2 = 0. U2 = 0 because the gravitational potential falls off like 1/r which goes to zero at infinity.

So we have (1/2)m*v^2 = GmM/R

so v^2 = 2GM/R

v = sqrt(2GM/R)

3. Nov 17, 2004

### ElectricMile

still not sure how you got rid of the 1/2...and did the m just cancel out on each side?

4. Nov 17, 2004

### Zlex

(1/2)m*v^2 = GmM/R

1] Divide both sides by m

(1/2)*v^2 = GM/R

2] Times both sides by 2

v^2 = 2GM/R

3] Take the root

v = sqrt(2GM/R)

5. Nov 17, 2004