Stumped on Moments / Forces diagram qn. Help

[Deathfish]

1. 1. Homework Statement

Ok. I'm given a force diagram, and I have to figure out the reaction forces at the two points on the ground.

answer key: (498.1N↑; 104.2N→, 92.8N↑)

Homework Equations

Ok. I only got so far as the x-reaction force at the pivot... 600 sin 10 = <- 104.2N

The Attempt at a Solution

Total y-reaction forces - 600 cos 10 = 590.88N

600 cos 10 = 590.88N
600 sin 10 = 104.2N

root 0.2^2 x 0.3^2 = 0.36m

104.19N x 0.3m = 31.257Nm
590.88N x 0.2m = 118.177 Nm

498.1N + 92.8N = 590.9N

i can't figure out how to get 498.1N and 92.8N at the two points respectively...
anyone can show how to achieve the answer? Thx

 

[PhanthomJay]

Sum of moments about any point = 0. Try summing moments of all forces about the hinge to solve for the vertical reaction at the left support. Watch plus and minus signs (ccw and cw moments). Don't forget the moment from both the vertical and horizontal components of the appied force.