A Man is on a 24 metre tall Building, and is going to swing from the top of this building to the Bottom of an Identical building on a rope. the Buildings are 24 metres apart, His rope is 24 metres long. He starts from Rest with the rope horizontal, but the rope will break if the tension force in it is twice the weight of the teacher. How high is the swinging man above ground level when the rope breaks?(adsbygoogle = window.adsbygoogle || []).push({});

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Hint, Aparently you use

½mv² = mgh

where h = r-rcosθ

m = mass

g = 9.81 m/s²

v = velocity

h = height

r = radius (24 metres)

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# Homework Help: Stumped on Question!

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