- #1

- 6

- 0

f(x)= cosx(3cos3x) + (sin3x)(-sinx)

i then have to find f(pi/6), but im hoping i can do that once this is simplified...

thanks

Gill

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- Thread starter Gill
- Start date

- #1

- 6

- 0

f(x)= cosx(3cos3x) + (sin3x)(-sinx)

i then have to find f(pi/6), but im hoping i can do that once this is simplified...

thanks

Gill

- #2

- 80

- 0

Gill said:

f(x)= cosx(3cos3x) + (sin3x)(-sinx)

i then have to find f(pi/6), but im hoping i can do that once this is simplified...

thanks

Gill

I wonder you made a typo.... is cosx(3cos3x) [tex]\cos(x*3\cos(3x))[/tex] or [tex]\cos(x)*3\cos(3x)[/tex]? Please place braces and it will clarify. But as for f(pi/6), it looks easy in any typo cases, because [tex]\cos(3*\pi/6) = 0, \sin(3*\pi/6) = 1[/tex]

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