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Stupid question

  1. Oct 3, 2009 #1
    I was reading div grad curl and all that. Couldn't get something basic - cross product.

    U = iux + k df/dx (ux)
    V = jvy + k df/dy (vy)

    UxV = [ -i df/dx - j df/dy + k] uxvy

    can't figure out how to get U x V.
     
  2. jcsd
  3. Oct 3, 2009 #2

    tiny-tim

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    Hi likephysics! :smile:

    (have a curly d: ∂ and try using the X2 tag just above the Reply box :wink:)
    (Let's ignore the common factor, uxvy)

    The i component of UxV is UjVk - VjUk, = 0 - ∂f/∂x.

    Can you do the others now? :smile:
     
  4. Oct 3, 2009 #3
    Thanks a bunch. Now I feel less stupid. yay!
     
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