Hi, I'm back with another question (IB Math Methods). It's kind of easy and I don't know if I'm stupid or having a brain lapse but it is this:(adsbygoogle = window.adsbygoogle || []).push({});

When finding the inverse of h(x) = [tex](/sqrt{x-1})[/tex], x > -1,

I got y = x^2 + 1, but what do I do with that x > -1 ??? THANKS!

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# Stupid-yet-needs-to-be-answered Question

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