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SU(2) expression

  1. Oct 22, 2014 #1
    Please, I'm stuck. How to get the rhs from the lhs?

    X^{\alpha}_{\ \ \alpha^{\ \prime}}X^{\beta}_{\ \ \beta^{\ \prime}}\epsilon^{\alpha^{\ \prime}\beta^{\ \prime}}=det X\epsilon^{\alpha\beta}
  2. jcsd
  3. Oct 22, 2014 #2


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  4. Oct 22, 2014 #3

    Meir Achuz

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    That is one of the definitions of a determinant. The left-hand side is just how you would calculate the value of a determinant. In your case, it is the determinant of a 2 x 2 matrix. Write out a sample case and you will see how it works.
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