- #1

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f(x) = { x^2 sin(1/x) x!=0, 0 x=0

Compute subdifferential f(0)

I went through my notes on subdifferentiation and still do not have a clue how to do this process, is there a formula to directly do this? any help would be greatly appreciated.

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- Thread starter braindead101
- Start date

- #1

- 162

- 0

f(x) = { x^2 sin(1/x) x!=0, 0 x=0

Compute subdifferential f(0)

I went through my notes on subdifferentiation and still do not have a clue how to do this process, is there a formula to directly do this? any help would be greatly appreciated.

- #2

Gib Z

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- #3

cristo

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(I know what people are going to say; don't link to wiki; but there doesn't really seem to be another website on this this is openly accessible!)

- #4

Gib Z

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What makes you (the OP) think that we can find the subderiavative at zero? Is the function convex...

- #5

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so i looked at the wiki you sent me and saw the example. but then i guess it is not the same

as my question as that function is convex and mine is not.

Example i am referring to:

Consider the function f(x)=|x| which is convex. Then, the subdifferential at the origin is the interval [−1, 1].

But with that said, I graphed the x^2sin(1/x) function to try to see the behaviour around 0, and both sides are approaching 0 and the slope seems to be also 0.. but i don't know if this is how to actually do it.

what are your thoughts after that wiki read?

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