let M={x[itex]^{2}[/itex]|x[itex]\in[/itex]G} where G is a group.(adsbygoogle = window.adsbygoogle || []).push({});

Show M is not a sub group if G=A[itex]_{4}[/itex](even permutations on 4 elements.)

(Since an even times an even is even its closed, the identity is even and all the inverses should be even.)* Is is associativity were it is going to go wrong? Or am I wrong in thinking *.

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# Homework Help: Subgroup Question

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