Submarine and torpedo

  • Thread starter mikefitz
  • Start date
  • #1
155
0
A submarine of mass 2.3 times 106 kg and initially at rest fires a torpedo of mass 260 kg. The torpedo has an initial speed of 100.9 m/s. What is the initial recoil speed of the submarine? Neglect the drag force of the water.

My work:

Pi=Pf
Pi=0
Pf= Mtorpedo * Vtorpedo - Msub * Vsub

Vsub = (260kg * (100.9 m/s) ) / 2.3 x 10^6

I get Vsub = .0114 m/s

Why is this wrong?? Thanks
 

Answers and Replies

  • #2
Doc Al
Mentor
45,208
1,545
Looks OK to me. Why do you think it's wrong?
 
  • #3
155
0
Stupid online homework system, I had to take the answer out a few more decimal places.

Thanks for your help Doc Al, appreciate it.
 

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