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Substitute gamma = t^2

  1. Apr 10, 2010 #1
    Hello,

    How to integrate the following integral (or what to use in the table of integrals):

    [tex]\int_0^{\infty}\underbrace{\mbox{erfc}\left(\sqrt{\gamma}\right)}_{Complementary Error Function}\,\mbox{e}^{-\gamma}\,d\gamma[/tex]?

    Thanks in advance
     
  2. jcsd
  3. Apr 10, 2010 #2
    Re: Integration

    Substitute gamma = t^2 and then do a partial integration where you integrate te factor t exp(-t^2).
     
  4. Apr 11, 2010 #3
    Re: Integration

    It is solved straightforward by using integration by parts and the Leibniz's rule.

    Thanks
     
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